将字符串存储到c中的数组中

Question

As i know, i can create an array with item inside such as:

char *test1[3]= {"arrtest","ao", "123"};

but how can i store my input into array like code above because i only can code it as

input[10];
scanf("%s",&input) or gets(input);

and it store each char into each space.

How can i store the input "HELLO" such that it stores into input[0] but now

H to input[0],E to input[1], and so on.

Answer 1

You need a 2 dimensional character array to have an array of strings:

#include <stdio.h>

int main()
{
    char strings[3][256];
    scanf("%s %s %s", strings[0], strings[1], strings[2]);
    printf("%s\n%s\n%s\n", strings[0], strings[1], strings[2]);
}

Answer 2

Use a 2-dimensional array char input[3][10];
or
an array of char pointers (like char *input[3]; ) which should be allocated memory dynamically before any value is saved at those locations.

First Case, take input values as scanf("%s", input[0]); , similarly for input[1] and input[2] . Remember you can store a string of max size 10 (including '\\0' character) in each input[i] .

In second case, get input the same way as above, but allocate memory to each pointer input[i] using malloc before. Here you have flexibility of size for each string.

Answer 3

Did not really understand what you need. But here is what I guessed.

char *a[5];//array of five pointers

for(i=0;i<5;i++)// iterate the number of pointer times in the array
{
char input[10];// a local array variable
a[i]=malloc(10*sizeof(char)); //allocate memory for each pointer in the array here
scanf("%s",input);//take the input from stdin
strcpy(a[i],input);//store the value in one of the pointer in the pointer array
}

Answer 4

try below code:

char *input[10];
input[0]=(char*)malloc(25);//mention  the size you need..
scanf("%s",input[0]);
printf("%s",input[0]);

Answer 5

int main()
{

int n,j;
cin>>n;
char a[100][100];
for(int i=1;i<=n;i++){
    j=1;
    while(a[i][j]!=EOF){
        a[i][j]=getchar();
        j++;
    }
}

Answer 6

This code inspired me on how to get my user input strings into an array. I'm new to C and to this board, my apologies if I'm not following some rules on how to post a comment. I'm trying to figure things out.

#include <stdio.h>

int main()

{

char strings[3][256];

scanf("%s %s %s", strings[0], strings[1], strings[2]);

printf("%s\n%s\n%s\n", strings[0], strings[1], strings[2]);

}