[英]php Class not working functions
I got some strange problems. 我遇到了一些奇怪的问题。 Using my class i connecting to mysql, connection is successful but when i call a function its not works.
使用我的类我连接到mysql,连接成功但是当我调用一个函数时它不起作用。 Im using my own error handler and if i got in php some error on this line it using exit;
我使用自己的错误处理程序,如果我在这行中有一些错误,它使用退出; i have used echo before calling function and after page is not killing (it means that php work successful) mysql query i have checked its works too but when im using return 'some text';
我在调用函数之前使用了echo并且在页面没有查杀之后(这意味着php工作成功)mysql查询我已经检查了它的工作但是当我使用返回'some text'时; its not returning.
它没有回来。 any suggestions why function is not working?
有什么功能不起作用的建议?
my class: 我的课:
<?php
include('../config.php');
include('../chat_error_handler.php');
class Chat {
private $mysqli;
var $con;
//Constructor open db conn
function __construct() {
$this->mysqli = new mysqli('localhost', 'root', '', 'test');
}
//destructor close db conn
function __destruct() {
$this->mysqli->close();
}
public function postNewMessage($user_name, $message, $color, $room_id) {
$user_name = $this->mysqli->real_escape_string($user_name);
$message = $this->mysqli->real_escape_string($message);
$color = $this->mysqli->real_escape_string($color);
$room_id = $this->mysqli->real_escape_string($room_id);
$query = 'INSERT INTO chat (posted_on, account, message, color, room_id)' .
' VALUES (NOW(), "'.$user_name.'", "'.$message.'", "'.$color.'", "'. $room_id .'")';
$result = $this->mysqli->query($query);
return 'Pranesimas';
$result->close();
}
My php im using to debug: 我的php我用来调试:
<?php
include('core/chat.class.php');
include('chat_error_handler.php');
$chat = new Chat();
$message = 'testas';
echo $message.'<br/>';
$chat->postNewMessage('testing', $message, '#000000', 1);
echo '<br/>'.$message;
?>
public function postNewMessage($user_name, $message, $color, $room_id) {
$user_name = $this->mysqli->real_escape_string($user_name);
$message = $this->mysqli->real_escape_string($message);
$color = $this->mysqli->real_escape_string($color);
$room_id = $this->mysqli->real_escape_string($room_id);
$query =
"INSERT INTO
chat ( posted_on,
account,
message,
color,
room_id )
VALUES ( NOW(),
'". $user_name ."',
'". $message ."',
'". $color ."',
'". $room_id ."' )";
$result = $this->mysqli->query($query);
if ( $result ) {
return 'Pranesimas';
} else {
return false;
}
}
About 'var'
in PHP5 and upper. 关于PHP5和上层的
'var'
。 It's for declaring class member variables in PHP4, and is no longer needed. 它用于在PHP4中声明类成员变量,不再需要它。 It will work in PHP5, but will raise an
E_STRICT
warning in PHP from version 5.0.0
up to version 5.1.2
, as of which it has been deprecated. 它将在PHP5中运行,但会在PHP中从版本
5.0.0
到版本5.1.2
引发E_STRICT
警告,因为它已被弃用。
UPDATE: 更新:
public function postNewMessage($user_name, $message, $color, $room_id) {
return 'Pranesimas1';
$user_name = $this->mysqli->real_escape_string($user_name);
$message = $this->mysqli->real_escape_string($message);
$color = $this->mysqli->real_escape_string($color);
return 'Pranesimas2';
$room_id = $this->mysqli->real_escape_string($room_id);
$query = 'INSERT INTO chat (posted_on, account, message, color, room_id)' .
' VALUES (NOW(), "'.$user_name.'", "'.$message.'", "'.$color.', "'. $room_id .'")';
$result = $this->mysqli->query($query);
return 'Pranesimas';
$result->close();
}
Try add return step by step for detect where is problem and let me know about result. 尝试逐步添加返回以检测问题所在并让我知道结果。
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