Symfony2 ::加载自定义表单类型时添加资产

Question

I've created a service for loading a custom form-type. But is it possible whenever I call this service, that automatically some javascript is autmaticlly loaded in mine block 'footer_javascripts' ? Because I don't want to load every time all the javascript.

At the moment, I'm doing it like this:

{% block wysiwyg_widget %}
    {% block footer_javascripts %}
       <script src="{{ asset('bundles/acme/js/demo/demo1.js') }}"></script>
       <script src="{{ asset('bundles/acme/js/demo/demo2.js') }}"></script>
   {% endblock %}
{% endblock %}

But now the code is in the content, and I would like it in the block 'footer_javascript' and calling {{ parent() }} doesn't work.

Thanks in advance

Answer 1

You can combine your Javascript files (and also CSS files) to reduce the number of HTTP requests.

You can use a variable to decide if the Javascript need to be loaded.

First, define it on your controller:

public function homepageAction($no_locale = false)
{
    [...]

    $customFormType = null;

    if (/* test if you used the custom form-type */)
    {
            $customFormType = true;
    }

    return $this->render('SCACWebsiteBundle:Default:homepage.html.twig',
        array(
            'form' => $form,
            'customFormType ' => $customFormType
        )
    );
}

Then you can test the variable in Twig:

{% if ((customFormType is defined) and (customFormType)) %}
    {% javascripts
        'bundles/acme/js/demo/demo1.js'
        'bundles/acme/js/demo/demo2.js' %}
        <script src="{{ asset_url }}"></script>
    {% endjavascripts %}
{% endif %}

By using (customFormType is defined) , you don't need to declare the variable in all of your controller. This test ensures that there will be no error if the variable is not defined. The condition (customFormType) will be true only if the custom form-type will be loaded, even if it's the same controller, with or without the custom form-type. If the custom form-type is not loaded, customFormType will have the null value and the result of the condition will be false.