[英]Filter list items by length in Haskell
I have a list like ["a","ab","abc", "abcd"]
我有一个像
["a","ab","abc", "abcd"]
How to get a list that only has the items which have a length > 2. 如何获取仅包含长度> 2的项目的列表。
Means the result is ["abc","abcd"].
意味着结果是
["abc","abcd"].
Natalie's answer is perfectly correct, but as an alternate form you could also write it as 娜塔莉的回答是完全正确的,但作为一种替代形式,你也可以把它写成
filter ((> 2) . length) ["a", "ab", "abc", "abcd"]
Or with list comprehension as 或者列表理解为
[str | str <- ["a", "ab", "abc", "abcd"], length str > 2]
All three are equivalent 这三个都是等价的
filter (\x -> length x > 2) ["a","ab","abc", "abcd"]
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