使用fscanf（）使用C解析逗号分隔文件

Question

I have a file with data something like this -

Name, Age, Occupation
John, 14, Student
George, 14, Student
William, 23, Programmer

Now, I want to read the data such that each value (eg Name, Age etc.) are read as a string.
This is my code snippet -

....
if (!(ferror(input_fp) || ferror(output_fp))) {
    while(fscanf(input_fp, "%30[^ ,\n\t]%30[^ ,\n\t]%30[^ ,\n\t]", 
                name, age_array, occupation) != EOF){
        fprintf(stdout, "%-30s%-30s%-30s\n", name, age_array, occupation);
    }
    fclose(input_fp);
    fclose(output_fp);
}
....

However, this goes into an infinite loop giving some random output.
This is how I understand my input conversion specifiers .
%30[^ ,\\n\\t] -> read a string that is at the maximum 30 characters long and that
DOES NOT include either a space, a comma, a newline or a tab character.
And I am reading 3 such strings.
Where am I going wrong?

Answer 1

OP's

fscanf(input_fp, "%30[^ ,\n\t]%30[^ ,\n\t]%30[^ ,\n\t]", ...

does not consume the ',' nor the '\\n' in the text file. Subsequent fscanf() attempts also fail and return a value of 0, which not being EOF , causes an infinite loop.

---

Although OP requested a fscanf() solution, a fgets()/sscanf() better handles potential IO and parsing errors.

FILE *input_fp;
FILE *output_fp;
char buf[100];
while (fgets(buf, sizeof buf, input_fp) != NULL) {
  char name[30];  // Insure this size is 1 more than the width in scanf format.
  char age_array[30];
  char occupation[30];
  #define VFMT " %29[^ ,\n\t]"
  int n;  // Use to check for trailing junk

  if (3 == sscanf(buf, VFMT "," VFMT "," VFMT " %n", name, age_array,
      occupation, &n) && buf[n] == '\0') {
    // Suspect OP really wants this width to be 1 more
    if (fprintf(output_fp, "%-30s%-30s%-30s\n", name, age_array, occupation) < 0)
      break;
  } else
    break;  // format error
}
fclose(input_fp);
fclose(output_fp);

Rather than call ferror() , check return values of fgets() , fprintf() .

Suspect OP's undeclared field buffers were [30] and adjusted scanf() accordingly.

---

[edit]

Details about if (3 == sscanf(buf, VFMT "," ...

The if (3 == sscanf(...) && buf[n] == '\\0') { becomes true when:
1) exactly the 3 "%29[^ ,\\n\\t]" format specifiers each scanf in at least 1 char each.
2) buf[n] is the end of the string. n is set via the "%n" specifier. The preceding ' ' in " %n" causes any following white-space after the last "%29[^ ,\\n\\t]" to be consumed. scanf() sees "%n" , which directs it to set the current offset from the beginning of scanning to be assign to the int pointed to by &n .

"VFMT "," VFMT "," VFMT " %n" is concatenated by the compiler to
" %29[^ ,\\n\\t], %29[^ ,\\n\\t], %29[^ ,\\n\\t] %n" .
I find the former easier to maintain than the latter.

The first space in " %29[^ ,\\n\\t]" directs sscanf() to scan over (consume and not save) 0 or more white-spaces ( ' ' , '\\t' , '\\n' , etc.). The rest directs sscanf() to consume and save any 1 to 29 char except ',' , '\\n' , '\\t' , then append a '\\0' .

Answer 2

You're not skipping the actual commas and spaces between the values.

Once the first %30[^ ,\\n\\t] specifier has matched, the input probably contains a comma and a space, which aren't matched by the following thing in the format string.

Add comma and space to the formatting string where expected in the input:

while(fscanf(input_fp, "%30[^ ,\n\t], %30[^ ,\n\t], %30[^ ,\n\t]", name, age_array, occupation) == 3)
                                    ^             ^
                                    |             |
                                    \             /
                                   add these to make
                                   fscanf() skip them
                                      in the input!

Also, your check of fscanf() 's return value is sub-optimal: before relying on the values to have been converted, you should check that the return value equals the number of conversions.

Plus, your use of the backslash line-continuation character is completely pointless and should be removed.