scanf 和 scanf_s 的区别

Question

What is the difference between scanf and scanf_s ? In the university I have been taught and I am using scanf , but at my personal computer Visual Studio keeps sending this warning.

 error C4996: 'scanf': This function or variable may be unsafe. Consider using scanf_s instead.

And I have to change all scanf to scanf_s or the program won't build. (I am using Visual Studio 2013)

Answer 1

It is a function that belongs specifically to the Microsoft compiler.

scanf originally just reads whatever console input you type and assign it to a type of variable.

If you have an array called first_name[5] and you use scanf for "Alex", there is no problem. If you have the same array and assign "Alexander", you can see it exceeds the 5 slots that the array contains, so C will still write it on memory that doesn't belong to the array and it might or might not crash the program, depending if something tries to access and write on that memory slot that doesn't belongs to first_name. This is where scanf_s comes in.

scanf_s has an argument(parameter) where you can specify the buffer size and actually control the limit of the input so you don't crash the whole building.

Answer 2

scanf_s() is not described by the C99 Standard (or previous ones).

If you want to use a compiler that targets C99 (or previous) use scanf() .

For C11 Standard (and eventually later ones) scanf_s() is much harder to use than scanf() for improved security against buffer overflows.

C11 fscanf_s() : http://port70.net/~nsz/c/c11/n1570.html#K.3.5.3.2

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If you have a C99 compiler with extras that provides scanf_s() as an extension and don't mind losing portability, check your compiler documentation.

Answer 3

What you can do to avoid this error is to paste the thing between the <>: <_CRT_SECURE_NO_WARNINGS> to a place. To get to the place right click on your project in the solution explorer and click on the properties. then go to the configuration properties, then the c/c++, then the preprocessor. then in preprocessor definitions, after everything, add a semicolon and paste the thing in. then press apply and ok. Your problem should be solved.

Answer 4

BTW, the reason your compiler is giving you an error, and stopping, rather than the 'warning' the issue actually is, is that you must have your Visual Studio setup such that it will "treat all warnings as errors". Change the configuration to let warnings be warnings, and you can then also just ignore this warning.