简体   繁体   English

Pandas Groupby 值范围

[英]Pandas Groupby Range of Values

Is there an easy method in pandas to invoke groupby on a range of values increments? pandas 中是否有一种简单的方法可以在一系列值增量上调用groupby For instance given the example below can I bin and group column B with a 0.155 increment so that for example, the first couple of groups in column B are divided into ranges between '0 - 0.155, 0.155 - 0.31 ...`例如,在下面的示例中,我可以以0.155增量对B列进行分组和分组,例如, B列中的前几组被划分为“0 - 0.155、0.155 - 0.31 ...”之间的范围

import numpy as np
import pandas as pd
df=pd.DataFrame({'A':np.random.random(20),'B':np.random.random(20)})

     A         B
0  0.383493  0.250785
1  0.572949  0.139555
2  0.652391  0.401983
3  0.214145  0.696935
4  0.848551  0.516692

Alternatively I could first categorize the data by those increments into a new column and subsequently use groupby to determine any relevant statistics that may be applicable in column A ?或者,我可以首先按这些增量将数据分类到一个新列中,然后使用groupby来确定可能适用于A列的任何相关统计数据?

You might be interested in pd.cut :您可能对pd.cut感兴趣:

>>> df.groupby(pd.cut(df["B"], np.arange(0, 1.0+0.155, 0.155))).sum()
                      A         B
B                                
(0, 0.155]     2.775458  0.246394
(0.155, 0.31]  1.123989  0.471618
(0.31, 0.465]  2.051814  1.882763
(0.465, 0.62]  2.277960  1.528492
(0.62, 0.775]  1.577419  2.810723
(0.775, 0.93]  0.535100  1.694955
(0.93, 1.085]       NaN       NaN

[7 rows x 2 columns]

Try this:尝试这个:

df = df.sort_values('B')
bins =  np.arange(0, 1.0, 0.155)
ind = np.digitize(df['B'], bins)
    
print df.groupby(ind).head() 

Of course you can use any function on the groups not just head .当然,您可以对组使用任何函数,而不仅仅是head

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM