从Python的字符串开头或结尾删除字符

Question

I have a string that for example can have - any where including some white spaces. I want using regex in Python to remove - only if it is before all other non-whitespace chacacters or after all non-white space characters. Also want to remove all whitespaces at the beginning or the end. For example:

string = '  -  test '

it should return

string = 'test'

or:

string = '  -this - '

it should return

string = 'this'

or:

string = '  -this-is-nice - '

it should return

string = 'this-is-nice'

Answer 1

You don't need regex for this. str.strip strip removes all combinations of characters passed to it, so pass ' -' or '- ' to it.

>>> s = '  -  test '
>>> s.strip('- ')
'test'
>>> s = '  -this - '
>>> s.strip('- ')
'this'
>>> s =  '  -this-is-nice - '
>>> s.strip('- ')
'this-is-nice'

To remove any type of white-space character and '-' use string.whitespace + '-' .

>>> from string import whitespace
>>> s =  '\t\r\n  -this-is-nice - \n'
>>> s.strip(whitespace+'-')
'this-is-nice'

Answer 2

import re
out = re.sub(r'^\s*(-\s*)?|(\s*-)?\s*$', '', input)

This will remove at most one instance of - at the beginning of the string and at most one instance of - at the end of the string. For example, given input - - text - - , the output will be - text - .

Note that \\s matches Unicode whitespaces (in Python 3). You will need re.ASCII flag to revert it to matching only [ \\t\\n\\r\\f\\v] .

Since you are not very clear about cases such as -text , -text- , -text - , the regex above will just output text for those 3 cases.

For strings such as text , the regex will just strip the spaces.