如何正确使用结构指针？

Question

I got confused with pointers while doing this code:

typedef struct Times{
    char time[100];
}Time;

Time *ptTimes(int tam, FILE *caminho){
    Time *times;
    times = (Time *)malloc((tam)*(sizeof(Time)));

    int i = 0;
    while(i < tam){
        fscanf(caminho, " %[^;];", (times->time));
        i++;
    }

    i=0;
    while (i < tam){
        printf("%s", times->time);
        times++;
        i++;
    }

    return(times);
}

The function *ptTimes was supposed to return a Time structure-pointer. What I intended to do was to creat a struct-pointer called *times and then make it point to several other structures allocated by malloc . I was trying to go through the allocated spaces and store the strings time[100] from a file. tam is the number of chars the program was supposed to read, it is a parameter sent from the main function.Also, I was trying to print in the screen what the structures have stored with printf .

I know I'm doing it wrong, the only thing printf showed on the screen was the last string on the file's list.

Here is an example of the .txt file:

Team1;
Team2;
Team3;
Team4;

I'm open for suggestions or ideas. I do need to use structures in this code.

Answer 1

EDIT: switched answer from pointer array to object array.

This line of code will always write to the first element in 'times', no matter the value of 'i':

fscanf(caminho, " %[^;];", (times->time));

It is equivalent to this line:

fscanf(caminho, " %[^;];", (times[0].time));

This is probably what you want:

fscanf(caminho, " %[^;];", (times[i].time));

You also need to get rid of the 'times++' line. The times pointer should continue to point to the memory that it allocated until you free it.

Answer 2

将times[i].time times->time更改为times[i].time ，并在第二个循环结束时删除times++ 。