Shell Scripting：打印具有特定内容的目录名称和文件

Question

In my script, I am asking the user to input a directory and then list all the files in that specific directory. What I want to do with that is to make the display a little better in which I would be able to display a "/" if the item in the directory is another directory and if it is an executable file (not an executable directory), print with a **".

This is what I have:

echo “Directory: “
read thing
for var123 in $thing*
do
        echo $var123
done

In a directory I have a few folders and a few scripts that have the execute permission. when I run the script I want to say

/folder1/subfolder1/

/folder1/subfolder2/

/folder1/file1*

/folder1/file2*

I am new to this and have no clue what I am doing. Any help will be greatly appreciated.

Answer 1

ls -F is your friend here - if you want to do it for the current directory:

ls -F

If you want to do it for all files & subfolders of the current directory:

find * -exec ls -Fd {} \;

... and for a given directory:

echo "Directory: "
read DIR

find $DIR/* -exec ls -Fd {} \;

Edit: ls -F will append a / to directories and a * to executables. If you want ** instead, just use sed to replace them:

find $DIR/* -exec ls -Fd {} \; | sed 's/\*$/&&/'

And this approach works in all shells, not just bash.

Answer 2

You might want to check and make sure the user inputs something that ends in a / first.

eg

[[ $thing =~ '/'$ ]] || thing="$thing/"

Also check if it exists

eg

[[ -d $thing ]] || exit 1

Then for checking if it's a directory use the -d test as above. To check if executable file use -x . So putting that all together, try:

#!/bin/bash
echo “Directory: “
read thing
[[ $thing =~ '/'$ ]] || thing="$thing/"
[[ -d $thing ]] || exit 1
for var123 in "$thing"*
do
  if [[ -f $var123 && -x $var123 ]]; then 
    echo "$var123**"
  elif [[ -d $var123 ]]; then 
    echo "$var123/"
  else
    echo "$var123"
 fi
done