如何通过php函数获取特定目录路径中的文件信息，例如文件mime类型和文件名？

Question

例如，使用php扫描/ favor目录以获取此文件夹内未知文件的名称和类型。

Answer 1

You could make use of finfo_file() in PHP.

<?php
$finfo = finfo_open(FILEINFO_MIME_TYPE); // return mime type ala mimetype extension
foreach (glob("*") as $filename) {
    echo finfo_file($finfo, $filename) . "\n";
}
finfo_close($finfo);
?>

OUTPUT:

text/html
image/gif
application/vnd.ms-excel

Answer 2

Try this it'll get the file name and extensions

$files=glob("files/*");    // files is directory name and * mean all types of files    
foreach ($files as $file) {
    echo $file."<br />";
}

It'll return file name and format!!!