如何在SQL Server 2008中使用三元运算符？

Question

SQL query:

SELECT * 
FROM Account 
WHERE (type <>100000002 ? Id='something': Id=null)

but it shows error :

Incorrect syntax near '?'

Please help me.

Answer 1

This is for SQL Server. IIF is not available in SQL Server 2008 or earlier.

 SELECT * 
    FROM Account 
    WHERE 
    Id=IIF(type<> 100000002,"something",null )

If you are using SQL Server 2008 or earlier, then try this.

  SELECT * 
    FROM Account 
    WHERE (Id= CASE WHEN type <>100000002 THEN 'something'  ELSE null END)

Answer 2

You can do this :

SELECT * 
FROM Account 
where (type <>100000002 and Id='something') or (type =100000002 and id is null)

or

SELECT * 
FROM Account 
where  isnull(id,'_null_')= case when type <>100000002 then 'something' else  isnull(id,'_null_') end

Answer 3

SELECT * 
FROM Account 
WHERE (Id= CASE WHEN type <>100000002 THEN 'something'  ELSE null END)

Answer 4

Use the following:

SELECT * 
FROM Account 
WHERE (Id= CASE WHEN type != 100000002 THEN 'something'  ELSE null END)

or

SELECT * 
FROM Account 
WHERE (Id= CASE WHEN type <> 100000002 THEN 'something'  ELSE null END)

Answer 5

SELECT * 
FROM Account 
where (type <>100000002 and Id='something') or (type =100000002)

Answer 6

您可以使用案例...然后在sql中请参阅此链接http://blog.sqlauthority.com/2007/04/14/sql-server-case-statementexpression-examples-and-explanation/