[英]Inserting variable into regex (JavaScript) isn't working
This is my code: 这是我的代码:
var newLT = 'locTable'+(l+locations);
var findLT = 'locTable'+l;
var regex = new RegExp("/\b" + findLT + "\b/g");
locOrig = locOrig.replace(regex, newLT);
I'm trying to replace all instances of 'locTable(#number here)' with the newLT variable. 我正在尝试用newLT变量替换'locTable(#number here)'的所有实例。
So for example if this was in a string <input id="locTable3_0">
ideally I could replace just the 'locTable3' part which is stored in findLT with the value in newLT. 因此,例如,如果在字符串
<input id="locTable3_0">
,则可以将newLT中的值仅替换存储在findLT中的'locTable3'部分。
Any tips on what I'm doing wrong? 关于我在做什么的任何提示?
EDIT: For clarity: 编辑:为清楚起见:
Say I have the string <input id="locTable3_0">
. 说我有字符串
<input id="locTable3_0">
。
variable newLT
is equal to locTable4 变量
newLT
等于locTable4
variable findLT
is equal to locTable3 变量
findLT
等于locTable3
I want to have a regex which finds locTable3 and replaces it with locTable4 so that my resulting string is <input id="locTable4_0">
我想有一个找到locTable3并将其替换为locTable4的正则表达式,以便我得到的字符串为
<input id="locTable4_0">
Updated: I think I god it now 更新:我想我现在知道了
var regex = /locTable\d/;
var newString = 'something_else_3'
var string = "locTable3_0";
var result = string.replace(regex1, newString);
this will result in something_else_3_0
这将导致
something_else_3_0
new RegExp("/\\b" + findLT + "\\b/g");
=> new RegExp("\\b" + findLT + "\\b", "g");
=>
new RegExp("\\b" + findLT + "\\b", "g");
new RegExp("\\b" + findLT + "\\b", "g");
=> new RegExp("\\\\b" + findLT + "\\\\b", "g");
=>
new RegExp("\\\\b" + findLT + "\\\\b", "g");
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