[英]Calculate execution time of a function in c++ (visual studio 2010)
I am coding in c++ and working on Visual Studio 2010. I am trying to compute the time that a function takes to execute, here is my code 我正在使用c ++编写代码并使用Visual Studio 2010.我正在尝试计算函数执行所需的时间,这是我的代码
double sum=0;
clock_t start_s=clock();
for(int j=1;j<size;j++)
{
int key=data[j];
int i=j-1;
while(i>=0 && data[i]>key)
{
data[i+1]=data[i];
i=i-1;
}
data[i+1]=key;
}
clock_t stop_s=clock();
sum=((double)(stop_s - start_s)/CLOCKS_PER_SEC);
but the problem is that the time computes to 0. How can I measure the time in even smaller unit 但问题是时间计算为0.如何以更小的单位测量时间
The clock()
will give you a resolution of 1 ms. clock()
将为您提供1 ms的分辨率。 If you want a higher resolution, use the QueryPerformanceCounter function, and QueryPerformanceFrequency 如果您想要更高的分辨率,请使用QueryPerformanceCounter函数和QueryPerformanceFrequency
One possible solution is to run this code segment, say for 100,000 times then calculate the average time 一种可能的解决方案是运行此代码段,比如说100,000次,然后计算平均时间
double sum=0;
clock_t start_s=clock();
int x = 0;
while (x < 100000)
{
for(int j=1;j<size;j++)
{
int key=data[j];
int i=j-1;
while(i>=0 && data[i]>key)
{
data[i+1]=data[i];
i=i-1;
}
data[i+1]=key;
}
x++;
}
clock_t stop_s=clock();
sum=((double)(stop_s - start_s)/CLOCKS_PER_SEC)/100000; //average time
It looks like clock()
is returning millisecond resolution ticks on Windows. 看起来
clock()
在Windows上返回毫秒级分辨率。
To get better granularity you should use the Windows high-resolution performance counter. 要获得更好的粒度,您应该使用Windows高分辨率性能计数器。 Call
QueryPerformanceFrequency
and QueryPerformanceCounter
. 调用
QueryPerformanceFrequency
和QueryPerformanceCounter
。
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