使用find（）在mongoDB中以字符串形式搜索唯一_id的列表

Question

I would like to find a list of different values with unique _id but the problem is that they are saved as String and if I try to search fe 10 it finds me also 100, 101, 102 etc.. In my case { "_id" : { "$gte" : "10" , "$lte" : "15"}} I would like to find 10, 11, 12, 13, 14, 15. But it finds me also 100, 110, 120 etc..

Thanks for your help

Answer 1

You have two more options:

• Issue a $regex query: {_id : /^1[0-5]/} (not sure about the PCRE syntax)
• Add a new field whose value is the numeric equivalent of _id and query that new field

Answer 2

You can do it using javascript expression

db.test.find("this._id > 10 && this._id < 15")

Please note that this will be a little slower