[英]MySQL: combining multiple values after a join into one result column
I have a database with a table for publications, each of which can have multiple authors that are stored in a different table.我有一个包含出版物表的数据库,每个出版物都可以有多个作者,这些作者存储在不同的表中。 I'd like to query the database into giving me a list of publication titles in one column, and the combined authors for that publication in the second.我想查询数据库,在其中一列给出出版物标题列表,在第二列中给出该出版物的联合作者。
SELECT p.`id`, p.`title`, a.`fullname`
from `publications` p
LEFT JOIN `authors` a on a.`publication_id` = p.`id`;
This of course gives me multiple times the publication title for as many authors.这当然给了我多次作者的出版物标题。
id title fullname
-- ----- --------
1 Beneath the Skin Sean French
1 Beneath the Skin Nicci Gerrard
2 The Talisman Stephen King
2 The Talisman Peter Straub
Grouping on id gives me one author per title:按 id 分组给我每个标题一个作者:
SELECT p.`id`, p.`title`, a.`fullname`
from `publications` p
LEFT JOIN `authors` a on a.`publication_id` = p.`id`
GROUP BY a.`id`;
id title fullname
-- ----- --------
1 Beneath the Skin Sean French
2 The Talisman Stephen King
The result I'm looking for is this:我正在寻找的结果是这样的:
id title fullname
-- ----- --------
1 Beneath the Skin Sean French, Nicci Gerrard
2 The Talisman Stephen King, Peter Straub
I think the answer should be found in using GROUP_CONCAT, but the only result I'm able to get is one result row with all authors:我认为答案应该在使用 GROUP_CONCAT 中找到,但我能得到的唯一结果是所有作者的一个结果行:
SELECT p.`id`, p.`title`, GROUP_CONCAT(a.`fullname`) from `publications` p
LEFT JOIN `authors` a on a.`publication_id` = p.`id`
GROUP BY a.`id`;
id title fullname
-- ----- --------
1 Beneath the Skin Sean French, Nicci Gerrard, Stephen King, Peter Straub
And using GROUP_CONCAT after the join gives me an "Every derived table must have its own alias" error.在连接后使用 GROUP_CONCAT 会给我一个“每个派生表都必须有自己的别名”错误。
SELECT p.`id`, p.`title`, a.`fullname`
FROM `publications` p
LEFT JOIN (SELECT GROUP_CONCAT(a.`fullname`) FROM `authors` a) ON a.`publication_id` = p.`id`;
Any clues?有什么线索吗?
You need to group by all of the non-aggregated columns in the SELECT (and explicitly, not group by the author id, because author is part of the GROUP_CONCAT):您需要按 SELECT 中的所有非聚合列进行分组(并且明确地,不是按作者 ID 分组,因为作者是 GROUP_CONCAT 的一部分):
SELECT p.`id`, p.`title`, GROUP_CONCAT(a.`fullname` separator ', ')
from `publications` p
LEFT JOIN `authors` a on a.`publication_id` = p.`id`
GROUP BY p.`id`, p.`title`;
Stuart's answer is fine.斯图尔特的回答很好。 This is just to show the working version of your approach:这只是为了展示您的方法的工作版本:
SELECT p.`id`, p.`title`, a.`fullname`
FROM `publications` p LEFT JOIN
(SELECT publication_id, GROUP_CONCAT(a.`fullname` separator ', ')
FROM `authors` a
GROUP BY publication_id
) a
--------^
ON a.`publication_id` = p.`id`;
The error you got was because the a
was missing after the subquery.您得到的错误是因为在子查询之后缺少a
。 The subquery also needed to be fixed, to include publication_id
in the select
and a group by
clause.还需要修复子查询,以在select
和group by
子句中包含publication_id
。
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