[英]Python - how to generate wordlist from given characters of specific length
I want to perform a dictionary attack and for that I need word lists. 我想进行字典攻击,为此我需要单词列表。 How to generate word list from given characters of specific length ( or word length from min length to max length )? 如何从特定长度(或从最小长度到最大长度的字长)的给定字符生成单词列表? I have tried itertools.combinations_with_replacements
and itertools.permutations
, but it does not help. 我已经尝试过itertools.combinations_with_replacements
和itertools.permutations
,但它没有帮助。 They does not have all the word lists that it should return. 他们没有应该返回的所有单词列表。 Any help will be greatly appreciated. 任何帮助将不胜感激。 Thank you. 谢谢。
Use itertools.product
: 使用itertools.product
:
>>> import itertools
>>>
>>> chrs = 'abc'
>>> n = 2
>>>
>>> for xs in itertools.product(chrs, repeat=n):
... print ''.join(xs)
...
aa
ab
ac
ba
bb
bc
ca
cb
cc
To get word from min length to max length: 从最小长度到最大长度获取单词:
chrs = 'abc'
min_length, max_length = 2, 5
for n in range(min_length, max_length+1):
for xs in itertools.product(chrs, repeat=n):
print ''.join(xs)
from itertools import product
def allwords(chars, length):
for letters in product(chars, repeat=length):
yield ''.join(letters)
def main():
letters = "abc"
for wordlen in range(3, 5):
for word in allwords(letters, wordlen):
print(word)
if __name__=="__main__":
main()
returns 回报
aaa
aab
aac
aba
abb
...
ccbc
ccca
cccb
cccc
This is a naïve implementation: 这是一个天真的实现:
list='abcdefg'
depth=8
def generate(l,d):
if d<1:
return
for c in l:
if d==1:
yield c
else:
for k in generate(l,d-1):
yield c+k
for d in range(1,depth):
for c in generate(list,d):
print c
I don't have enough reputation to comment yet, so, to make a full list based on the itertools sample above: 我还没有足够的声誉来评论,因此,要根据上面的itertools示例制作完整列表:
import itertools
chrs='abc'
n=6
for i in range(1,n):
for xs in itertools.product(chrs, repeat=i):
print ''.join(xs)
This way, you have all words from length 1 up to n in your list. 这样,您就可以在列表中拥有从长度1到n的所有单词。
def word_gen(start= 3,end= 3, elements = 1): """ Hud Seidu Daannaa Wordlist gen MSC InfoSec, CEH" def word_gen(start = 3,end = 3,elements = 1):“”“Hud Seidu Daannaa Wordlist gen MSC InfoSec,CEH”
README
#for start&end
#e.g. start= 3,end= 3
#means first words to last words should be 3 characters
#for elements
1 is asci
2 is numbers
3 is asci&numbers
"""
import itertools
#types of elements
if elements ==1: elements= 'abcdefghijklmnopqrstuvwxyx'
if elements ==2: elements= '0123456789'
if elements== 3: elements= 'abcdefghijklmnopqrstuvwxyx0123456789'
else: pass
wl = []
for i in range(start,end+1):
for xs in itertools.product(elements, repeat=i):
wl.append(''.join(xs))
return wl
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