SQL合并两个表中的数据

Question

I have two tables...

+-----------+-----------+
| employees | positions |
+-----------+-----------+
| id        | id        |
| fname     | pos       |
| lname     |           |
| hphone    |           |
| cphone    |           |
| email     |           |
| posid     |           |
+-----------+-----------+

I want to create a form to add a new employee and have a dropdown for the position so that you pick from a position that is listed in the positions table

I know how to make the dropdown box but i am not sure how to setup the sql and how to save it as a new record...can someone please help me?

The code im using for the dropdown is a function called getpos and it is...

function getpos(){
$sql=mysql_query("SELECT id,pos FROM positions"); 
if(mysql_num_rows($sql)){ 
$select= '<select name="select">';   
while($rs=mysql_fetch_array($sql)){ 
  $select.='<option value="'.$rs['id'].'">'.$rs['pos'].'</option>'; 
  } 
} 
$select.='</select>'; 
echo $select;
}

it works fine...to call it i use

this is the SQL i thought about...is it correct?

SELECT employees.id, employees.fname, employees.lname, employees.hphone,
employees.cphone, employees.email, employees.posid
FROM employees
INNER JOIN
positions ON positions.posid = employees.posid 

Answer 1

Use:

SELECT id, pos FROM positions ORDER BY pos DESC; 

to populate the the drop down list. The positions will be given in descending order.

I don't know which method you using for the form action (GET/POST). But on the next page you will retrieve $_GET['id'] or $_POST['id'] and insert that into your other table employees (posid).

Then you use the values from your form to insert into you database.

INSERT INTO (fname, flname, hphone,cphone,email, posid 
FROM employees 
VALUES (....values from the form ...); 

One of the variable you want to insert is the ID from positions.

If you want to SELECT the data from the database in order to display them in a table for instance you could use this query:

SELECT position.name, employees.fname, employees.flname,
employees.hphone, employees.cphone,employees.email 
FROM employees JOIN positions 
ON employees.posid = posistion.id;