如何一次遍历两个列表？

Question

Suppose I had two lists, foo and bar instantiated as follows:

foo = ['Hello', 'Yes', 'No']
bar = ['Bonjour', 'Oui', 'Non']

Suppose, then, I wanted to iterate through the values and print a concatenation like so:

count = 0
for x in foo:
    print x + bar[count]
    count += 1

Which would give me:

HelloBonjour

YesOui

NoNon

Would there be method that wouldn't require a count iterator? Perhaps something along the lines of...

for x in foo and y in bar:
    pint x + y

is available?

Answer 1

You can use zip :

foo = ['Hello', 'Yes', 'No']
bar = ['Bonjour', 'Oui', 'Non']
for x, y in zip(foo, bar):
    print x + y

Output:

HelloBonjour
YesOui
NoNon

Answer 2

Zip is something that will help you when both your input lists are of equal size. If lists are of different size the operation will be performed only on the elements that have pair in the other list. If you want to fill the missing pairs with something you can use map:

for i,j in map(None,listA,listB):  
    print i+j  

output:

HelloBonjour
YesOui
NoNon

Answer 3

您可以尝试这个人：

print '\n'.join( map(lambda x, y: x+y, foo, bar) )