[英]MYSQL: UPDATE MULTIPLE COLUMNS BASED ON IF
Good morning, I tell them my situation: I have two tables: 早上好,我告诉他们我的情况:我有两个桌子:
RATINGS:
GUIDE varchar(7)
USER varchar(20)
PRETEST decimal(4,3)
POSTEST decimal(4,3)
RATINGS_PERGUIDE:
USER varchar(20)
GUIDE1_PRETEST decimal(4,3)
GUIDE1_POSTEST decimal(4,3)
GUIDE2_PRETEST decimal(4,3)
GUIDE2_POSTEST decimal(4,3)3
.
.
.
GUIDE20_PRETEST decimal(4,3)
GUIDE20_POSTEST decimal(4,3)
Table "RATINGS" has a form for entering the information, I need to move the information entered to the table "RATINGS_PERGUIDE", i try this: 表“ RATINGS”具有用于输入信息的表格,我需要将输入的信息移至表“ RATINGS_PERGUIDE”,我尝试这样做:
UPDATE RATINGS , RATINGS_PERGUIDE
IF RATINGS.USER = RATINGS_PERGUIDE.USER AND RATINGS.GUIDE = 'GUIDE 1'
THEN
SET RATINGS_PERGUIDE.GUIDE1_PRETEST = RATINGS.PRETEST
SET RATINGS_PERGUIDE.GUIDE1_POSTEST = RATINGS.POSTEST
ELSE IF RATINGS.USER = RATINGS_PERGUIDE.USER AND RATINGS.GUIDE = 'GUIDE 2'
THEN
SET RATINGS_PERGUIDE.GUIDE2_PRETEST = RATINGS.PRETEST;
SET RATINGS_PERGUIDE.GUIDE2_POSTEST = RATINGS.POSTEST;
.
.
.
END IF
But doesn't work 但是不起作用
ie, according to the "GUIDE" entered in the table "RATINGS" update the corresponding column in the table "RATINGS_PERGUIDE" (24 "GUIDES" different) 即,根据表“ RATINGS”中输入的“ GUIDE”更新表“ RATINGS_PERGUIDE”中的相应列(24个“ GUIDES”不同)
Likewise, if it can be done in a trigger for each new record inserted into the table "RATINGS" would be much better 同样,如果可以在触发器中为插入到表“ RATINGS”中的每条新记录做得更好
Please Help 请帮忙
You are trying to do a pivot in an update
and that is a little complicated. 您正在尝试做一个update
的枢纽,这有点复杂。 One way is to simply do multiple updates: 一种方法是简单地进行多次更新:
update RATINGS_PERGUIDE join
RATINGS
on RATINGS.USER = RATINGS_PERGUIDE.USER and
RATINGS.GUIDE = 'GUIDE 1'
SET RATINGS_PERGUIDE.GUIDE1_PRETEST = RATINGS.PRETEST,
RATINGS_PERGUIDE.GUIDE1_POSTEST = RATINGS.POSTEST;
Modify and repeat this update for each of the guides. 为每个指南修改并重复此更新。
If you really want to do this in a single query: 如果您真的想在单个查询中执行此操作:
update RATINGS_PERGUIDE join
(select r.user,
max(case when r.GUIDE = 'GUIDE 1' then pretest end) as pretest_guide1,
max(case when r.GUIDE = 'GUIDE 1' then posttest end) as posttest_guide1,
max(case when r.GUIDE = 'GUIDE 2' then pretest end) as pretest_guide2,
max(case when r.GUIDE = 'GUIDE 2' then posttest end) as posttest_guide2,
. . .
from RATINGS r
group by r.user
) r
on r.USER = RATINGS_PERGUIDE.USER
SET RATINGS_PERGUIDE.GUIDE1_PRETEST = r.pretest_guide1,
RATINGS_PERGUIDE.GUIDE1_POSTEST = r.posttest_guide1,
RATINGS_PERGUIDE.GUIDE2_PRETEST = r.pretest_guide2,
RATINGS_PERGUIDE.GUIDE2_POSTEST = r.posttest_guide2,
. . .
I have found the solution by simply observing the structure of "Update" in Phpmyadmin 我已经通过简单地观察Phpmyadmin中“更新”的结构找到了解决方案
UPDATE RATINGS , RATINGS_PERGUIDE
SET RATINGS_PERGUIDE.GUIDE1_PRETEST = (CASE WHEN RATINGS.GUIDE = 'GUIDE 1' THEN RATINGS.PRETEST ELSE RATINGS_PERGUIDE.GUIDE1_PRETEST END),
RATINGS_PERGUIDE.GUIDE1_POSTEST = (CASE WHEN RATINGS.GUIDE = 'GUIDE 1' THEN RATINGS.PRETEST ELSE RATINGS_PERGUIDE.GUIDE1_POSTEST END),
RATINGS_PERGUIDE.GUIDE2_PRETEST = (CASE WHEN RATINGS.GUIDE = 'GUIDE 2' THEN RATINGS.PRETEST ELSE RATINGS_PERGUIDE.GUIDE2_PRETEST END),
RATINGS_PERGUIDE.GUIDE2_POSTEST = (CASE WHEN RATINGS.GUIDE = 'GUIDE 2' THEN RATINGS.PRETEST ELSE RATINGS_PERGUIDE.GUIDE2_POSTEST END),
. . . .
WHERE RATINGS.USER = RATINGS_PERGUIDE.USER
And this work for me, I put it in a stored procedure and then call with a trigger 对我来说,这是一项工作,我将其放入存储过程中,然后使用触发器进行调用
Thanks to All and to Gordon Linoff 感谢所有人和Gordon Linoff
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