在printf程序结束自身而不执行其余代码之后？ C

Question

after printf line program ends itself but i didnt get it why.

#include<stdio.h>

int main ()
{
    int Sum,multiply,divide,difference,num1,num2;
    char i;
    scanf("%d", &s1);
    scanf("%d", &s2);
    printf("Type initial of your operation : ");
    scanf("%c", &i);

    return 0 ;
}

Answer 1

There is no way you could compile that, since s1 and s2 are undefined variables.

Thus, any information about what happened when you ran it is moot, since there is no way you could run it.

You meant:

if(scanf("%d %d", &num1, &num2) == 2)
{
  printf("Operands are %d and %d, now type initial of desired operation:\n");
  if(scanf("%c", &i) == 1)
  {
  }
}

It's important to check that scanf() has succeeded before relying on the return value.

Answer 2

use scanf(" %c",&i); there is new line character is present in buffer,so it is not asking for any input and storing it in i.

Answer 3

s1 & s2 are not declared which you are trying to read into them. I feel they should be num1 & num2 which you been declared as integers.

After printf you just read a char value into i using scanf and main ends doing nothing.