如何使用XSLT处理命名空间的XML文档？
[英]How to process a namespaced XML document using XSLT?
问题描述
I am trying to process an XML file with XSLT to produce a list or table or (eventually) an SQL INSERT command with some of the values. 
我正在尝试使用XSLT处理XML文件以生成列表或表，或者最终生成带有某些值的SQL INSERT命令。 I have been using the example from w3schools http://www.w3schools.com/xsl/tryxslt.asp?xmlfile=cdcatalog&xsltfile=cdcatalog . 我一直在使用来自w3schools http://www.w3schools.com/xsl/tryxslt.asp?xmlfile=cdcatalog&xsltfile=cdcatalog的示例。
My XML is very simple and I need to extract just the name and the rate of the hotel: 我的XML非常简单，我只需要提取酒店的名称和价格即可：
<?xml version="1.0" encoding="utf-8"?>
<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<soapenv:Body>
<getHotelsResponse xmlns="http://hotel.booking.vbooking.com">
<getHotelsReturn>
<address>
<number>589-591</number>
<postcode>08014</postcode>
<region>Catalonia</region>
<street>Carrer Vermell</street>
<town>Barcelona</town>
</address>
<name>Downtown Hotel</name>
<rate>235.0</rate>
</getHotelsReturn>
</getHotelsResponse>
</soapenv:Body>
</soapenv:Envelope>
The best XSLT I could build up from the w3schools was this one: 我可以从w3schools建立的最好的XSLT是：
<?xml version="1.0" encoding="utf-8"?>
<!-- Edited by XMLSpyΠ-->
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/soapenv:Envelope/soapenv:Body/getHotelsResponse">
<html>
<body>
<h2>Hotels in Barcelona</h2>
<table border="1">
<tr bgcolor="#9acd32">
<th>Hotel name</th>
<th>Rate ($/night)</th>
</tr>
<xsl:for-each select="getHotelsReturn">
<tr>
<td><xsl:value-of select="name"/></td>
<td><xsl:value-of select="rate"/></td>
</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
Which should produce a similar result to what I had in the w3schools example, but it comes back as blank. 它将产生与w3schools示例中类似的结果，但返回空白。
Can anyone please explain this? 谁能解释一下？ Thanks. 谢谢。
2 个解决方案
解决方案1
3 已采纳 2014-02-06 15:43:32
As pointed out by @keshlam, if elements in your input XML have namespaces, you must declare them in your XSLT stylesheet as well. 正如@keshlam指出的那样，如果输入XML中的元素具有名称空间，则还必须在XSLT样式表中声明它们。
Find more detail on namespaces in a previous answer of mine . 在我的以前的答案中找到有关名称空间的更多详细信息。
The gist of the information you find there is: as far as the XSLT processor is concerned, a getHotelsReturn element is entirely different from a vb:getHotelsReturn element. 您所找到的信息的依据是：就XSLT处理器而言， getHotelsReturn元素与vb:getHotelsReturn元素完全不同。
Stylesheet 样式表
<?xml version="1.0" encoding="utf-8"?>
<!-- Edited by XMLSpy?-->
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:vb="http://hotel.booking.vbooking.com"
xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/"
exclude-result-prefixes="soapenv vb">
<xsl:template match="/soapenv:Envelope/soapenv:Body/vb:getHotelsResponse">
<html>
<body>
<h2>Hotels in Barcelona</h2>
<table border="1">
<tr bgcolor="#9acd32">
<th>Hotel name</th>
<th>Rate ($/night)</th>
</tr>
<xsl:for-each select="vb:getHotelsReturn">
<tr>
<td><xsl:value-of select="vb:name"/></td>
<td><xsl:value-of select="vb:rate"/></td>
</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
Output 产量
<html>
<body>
<h2>Hotels in Barcelona</h2>
<table border="1">
<tr bgcolor="#9acd32">
<th>Hotel name</th>
<th>Rate ($/night)</th>
</tr>
<tr>
<td>Downtown Hotel</td>
<td>235.0</td>
</tr>
</table>
</body>
</html>
Rendered HTML 呈现的HTML
解决方案2
-3 2014-02-06 15:33:09
You can use XPaths like this: 您可以像这样使用XPath：
/Product1/Product2/Product3[@ValidYN = 'Y' and @ProductType = 'ABC']
/Product1/Product2/Product3[@ValidYN = 'Y' and @ProductType = 'DEF']
/Product1/Product2/Product3[@ValidYN = 'Y' and @ProductType = 'GHI']
Check this other question How to parse XML using XSLT? 另一个问题请问如何使用XSLT解析XML？
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