从CSV文件中提取Unicode数据

Question

I have a CSV file like this encoding UTF-8

# id    english_word    part_of_speech  malayalam_definition
174569  .net    n   പുത്തന്‍ കമ്പ്യൂട്ടര്‍ സാങ്കേതികത ഭാഷ
116102  A bad patch n   കുഴപ്പം പിടിച്ച സമയം
115869  A bed of nails  n   പ്രയാസപ്പെടുന്ന അവസ്ഥ
200587  A bed of nails  idm ശരശയ്യ
115768  A bed of roses  n   സുഖകരമായ അവസ്ഥ
115767  A bed of roses  n   പൂമെത്ത
113832  A bed of thorn  n   അസുഖകരമായ അവസ്ഥ
113665  A bed roses n   പൂമെത്ത

I have to extract all Unicode data from the file having n tag

import csv
with open('some.csv', newline='\t', encoding='utf-8') as f:
    reader = csv.reader(f)
    for row in reader:
        print(row)

This is the code I have but it is not working The code is not producing output, it does not . Any suggestions ?

Python 2.7

Answer 1

You have to read the csv file before you iterate in it with for row in f .

First, import the csv package:

import csv

After, read the csv file:

with open('mycsv.csv','r') as f:
  with open('n.csv','w') as new_file:
    file_read = csv.reader(f,delimiter=';')
    for row in file_read:
      if not extract_n(row):
        new_file.write(row)

The delimiter field can be a semicolon, comma, o whatever you have.

Answer 2

In the original code , " n" in row does not match anything because there is a tab character before the n . If there is always a tab, try "\\tn" in row instead.

Now, the problem is that your code is a Python 3 version. In Python 2.7, the open function does not take a newline argument, hence the TypeError .

This should work with a tab-delimited file:

import csv
with open('some.csv', 'rb') as f:
    reader = csv.reader(f, delimiter='\t')
    for row in reader:
        if "n" in row:
            print(row)