为什么我的代码跳到最后而忽略了我的部分代码？

Question

Here is the code:

print "Welcome to the Database!"

print "Simply type the correponding number to start!"

print """

    1. Add a Student...

    2. Search for a Student...

    3. Edit a Student's Information...

    4. Delete a Student...

    5. Exit...
"""

datab = raw_input("What would you like to do?")

if datab == 1:
    dtabs = open("database.txt", "w")
    que = raw_input("What's the student's name?")
    dtabs.write(que)
    dtabs.close()

    ttrgrp = raw_input("Which tutor group do they belog to?")

When I run it in Terminal it prints the what would I like to do but then once an input is taken in the program closes.

Answer 1

raw_input() returns a string , but you are comparing against an integer. Python will not coerce strings when comparing:

>>> '1' == 1
False

Compare against a string here:

if datab == '1':

as this simplifies validation.

Answer 2

Everything inside of your if statement is being skipped, as datab will never be equal to 1 in its integer form. raw_input() will return the value string. Change your if statement to accept 1 as a string:

if datab == '1':
    #do something