bash脚本正则表达式

Question

I am not very familiar with Linux scripts using reg expressions,

but I need a script that will do this:

copy A/first_image.jpg  to B/first_image/thumb.jpg

copy A/second_image.jpg to B/second_image/thumb.jpg

etc.

every image in a folder A is copied in a directory with his name (in a directory B), and renamed to thumb.jpg

How can I do this?

Answer 1

You use filename "globbing", which is comparable to, but different from, regular expressions as such. You also use a loop and the command basename . Like this:

for file in A/*.jpg
do
    base=`basename $file .jpg`
    mkdir -p B/${base}
    cp A/${base}.jpg B/${base}/thumb.jpg
done

Answer 2

Run this script from parent directory of A, B, C etc:

for s in */*.jpg; do
    f="${s##*/}"
    d="${s%%/*}/${f%%.*}"
    mkdir -p "$d" 2>/dev/null
    cp "$s" "$d/thumb.jpg"
done