简体   繁体   English

Row_Number()在分区上-更简单的方法

[英]Row_Number() Over Partition - Easier Way

I have the below query: 我有以下查询:

INSERT into @TEST (col1,staffnumber,rn)
SELECT starttime as col1,staffnumber,ROW_NUMBER() OVER (PARTITION BY StaffNumber ORDER BY STARTTIME DESC) AS rn
  FROM @TempTable2 t2
UNION 
SELECT eventdate as col1, staffnumber,ROW_NUMBER() OVER (PARTITION BY StaffNumber ORDER BY EVENTDATE DESC) AS rn
  FROM @TempTable1 t1

But, obviously, this gives me the following values: 但是,显然,这给了我以下值:

COL1                | staffnumber    | rn
10/02/2014 10:29:24         1          1
10/02/2014 09:08:19         1          3
10/02/2014 10:00:23         1          2
10/02/2014 10:00:29         1          1

Whereas, I need it to show: 而我需要它来显示:

COL1                | staffnumber    | rn
10/02/2014 10:29:24         1          1
10/02/2014 09:08:19         1          4
10/02/2014 10:00:23         1          3
10/02/2014 10:00:29         1          2

I can do this by doing the following: 我可以通过执行以下操作来做到这一点:

INSERT into @TEST1 (col1,staffnumber,rn)
SELECT convert(time,col1),staffnumber,ROW_NUMBER() OVER (PARTITION BY StaffNumber ORDER BY convert(time,COL1) DESC) AS rn
FROM @TEST

But there must be an easier more efficient way of doing it. 但是必须有一种更简单,更有效的方法。 Any ideas? 有任何想法吗?

Compute the ROW_NUMBER after the UNION . UNION之后计算ROW_NUMBER

SELECT *, ROW_NUMBER() OVER (PARTITION BY StaffNumber ORDER BY STARTTIME DESC) AS rn
FROM (
 SELECT * FROM T1
 UNION ALL
 SELECT * FROM T2
) x

I suspect you need UNION ALL . 我怀疑您需要UNION ALL

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM