从两个单独的表中选择数据以用于MySQL / PHP中的新闻提要

Question

I would like to select datas from two separate tables to make a newsfeed like facebook which would display both photos, news or reviews (or anything) in one list and ordered by their date. Right now, I have two lists on my website which show photos and news separately. I'd like to have just one list which would contain all the items.

Here's a example:

news 1  : june 20
photo 1 : june 15
photo 2 : june 13
news 2  : june 12
photo 3 : june 9 
review 1: june 5

I tried this SQL query:

SELECT n.id, n.title, n.date, t.id_photo, t.url, t.date_photo 
FROM news AS n, photos AS t 
ORDER BY n.date DESC, t.date_photo DESC 
LIMIT 0,30

But this didn't work. Any idea?

NB: There's no link between those tables. There're completely different.

Answer 1

try this:

<?php
    $newsPage = isset($_GET['newspage']) ? $_GET['newspage'] : 0;
    $photosPage = isset($_GET['photospage']) ? $_GET['photospage'] : 0;
    $selectNews = mysqli_query("SELECT `news`.`id`, `news`.`title`, `news`.`date`
                                FROM `news`
                                ORDER BY `news`.`date` DESC
                                LIMIT ".$newsPage."0,10;");
    while($news = mysqli_fetch_assoc($selectNews)) {
        echo $news['title'].'<br />';
    }
    $selectPhotos = mysqli_query("SELECT `photos`.`id_photo`, `photos`.`url`, `photos`.`date_photo` 
                                FROM `photos`
                                ORDER BY `photos`.`date_photo` DESC
                                LIMIT ".$photosPage."0,10;");
    while($photos = mysqli_fetch_assoc($selectPhotos)) {
        echo '<img src="'.$photos['url'].'" alt="Image" title="Image" /><br />';
    }

Lemme know how it goes.