Matplotlib 从图中删除补丁

Question

In my case, I want to remove one of the circle when clicking reset button. However, ax.clear() would clear all circles on the current figure.

Can someone tell me how to remove only part of the patches?

import matplotlib.patches as patches
import matplotlib.pyplot as plt
from matplotlib.widgets import Button

fig = plt.figure()
ax = fig.add_subplot(111) 

circle1 = patches.Circle((0.3, 0.3), 0.03, fc='r', alpha=0.5)
circle2 = patches.Circle((0.4, 0.3), 0.03, fc='r', alpha=0.5)
button = Button(plt.axes([0.8, 0.025, 0.1, 0.04]), 'Reset', color='g', hovercolor='0.975')
ax.add_patch(circle1)
ax.add_patch(circle2)

def reset(event):
    '''what to do here'''
    ax.clear()

button.on_clicked(reset)
plt.show()

Answer 1

Try this:

def reset(event):
    circle1.remove()

Also maybe you prefer:

def reset(event):
    circle1.set_visible(False)

Answer 2

Different options is this

ax.patches = []

it removes all the patches.

Answer 3

I tried answer 1 as well, while it does work in this context it didn't work in my own code. What worked was to remove the patch object after adding the patch to the axis, rather than the original patch object, like this:

circle1 = patches.Circle((0.3, 0.3), 0.03, fc='r', alpha=0.5)
circle2 = patches.Circle((0.4, 0.3), 0.03, fc='r', alpha=0.5)
button = Button(plt.axes([0.8, 0.025, 0.1, 0.04]), 'Reset', color='g', hovercolor='0.975')
c1=ax.add_patch(circle1)
c2=ax.add_patch(circle2)

def reset(event):
    c1.remove()

button.on_clicked(functools.partial(reset,patch=c1))
plt.show()

otherwise I got NotImplementedError('cannot remove artist') error.