[英]Converting JavaScript function argument to php variable
I have a js function, which is passed a fileid to delete by a php script. 我有一个js函数,该函数传递了一个fileid以通过php脚本删除。 I don't know how to convert the javascript parameter from JavaScript to PHP variable.
我不知道如何将JavaScript参数从JavaScript转换为PHP变量。
Here is what I have done so far: 到目前为止,这是我所做的:
<script>
function deleteFile(file)
{
var r = confirm("Are you sure you want to delete this file?");
if (r === true)
{
<?php
$idfile = file; // How to convert it??
unlink(mysql_result(
mysql_query("SELECT filepath FROM
file where idfile='$idfile'"), 0, 0))
or die("Could not delete file");
mysql_query("DELETE FROM file WHERE fileid=$idfile")
or die("Cannot delete file");
echo "File has been deleted successfully.";
?>
}
}
</script>
I have a button also: 我也有一个按钮:
echo "<button onclick=\"deleteFile($fileid)\">Delete</button>";
UPDATE 更新
function deleteFile(file)
{
var r = confirm("Are you sure you want to delete this file?");
if (r === true)
{ // doesn't go to deletefile.php
$.ajax({
url: "/deletefile.php",
method: 'POST',
data: {
id: file
}
});
}
}
That won't work. 那行不通。 JavaScript and PHP are totally separate entities that execute at different times.
JavaScript和PHP是完全独立的实体,它们在不同的时间执行。
PHP is a server-side language. PHP是一种服务器端语言。 The PHP code executes on your server and returns a response to the web browser.
PHP代码在您的服务器上执行,并将响应返回到Web浏览器。
JavaScript is a client-side language. JavaScript是一种客户端语言。 It executes when the user is interacting with the page in their browser, after the PHP code has executed.
在PHP代码执行之后 ,当用户与浏览器中的页面进行交互时,它将执行。
You'll need to write a separate PHP script that takes the ID of the file to delete, then use AJAX to send the request to delete it with the specified file ID. 您需要编写一个单独的PHP脚本,该脚本使用要删除的文件ID,然后使用AJAX发送具有指定文件ID的删除请求。
You can't put a Javascript variable in PHP, but you can make an AJAX to send $id_file
: 您不能在PHP中放置Javascript变量,但是可以使AJAX发送
$id_file
:
$.ajax({
url: "/action.php",
method: 'POST',
data: {
id: file,
}
});
Then in the PHP action you can use the $_POST['id']
and make the query. 然后,在PHP操作中,您可以使用
$_POST['id']
进行查询。
It would be better to use AJAX for example with jQuery. 最好将AJAX与jQuery一起使用。 Code you created can't work, that way.
这样创建的代码无法正常工作。 Try this.
尝试这个。
Generating button with id 产生ID的按钮
<?php
echo '<button class="delete_button" data-id="'.$id.'">delete me!</button>';
?>
Download jQuery from here , save it into your project folder. 从这里下载jQuery,将其保存到您的项目文件夹中。
Sending post request using jQuery 使用jQuery发送帖子请求
<script type="text/javascript" src="/path/to/jquery.min.js"> <script type="text/javascript"> $(".delete_button").click(function() { var id = $(this).data("id"); $.post( "handler.php",{del: id}, function( data ) { if(data) { alert("deleted successfully!"); window.location = "/your/desired/url"; // redirect after success } } }); </script>
deleting in handler.php 在handler.php中删除
if(array_key_exists("del", $_POST))
{
// delete in mysql
}
function deleteFile(file)
{
var r = confirm("Are you sure you want to delete this file?");
if (r === true)
{ // doesn't go to deletefile.php
$.ajax({
url: "/deletefile.php",
method: 'POST',
data: {
id: file
}
})
.done(function( data ) {
console.log(data);
});
}
}
Php p
<?php
$idfile = $_POST['id']; // How to convert it??
unlink(mysql_result(
mysql_query("SELECT filepath FROM
file where idfile='$idfile'"), 0, 0))
or die("Could not delete file");
mysql_query("DELETE FROM file WHERE fileid=$idfile")
or die("Cannot delete file");
?>
doesn't go to deletefile.php ? 不去deletefile.php吗? maybe the url is not the correct
网址可能不正确
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