注意：数组到字符串转换PHP

Question

I am loading a friends site to play with it and it gives me this: Notice: Array to string conversion error. Any idea's how to fix this? (my friend is out of town)

function href($filename) {
    if (@$_SERVER['HTTPS'] != 'on') {
        return HTTP_IMAGE . $filename;
    } else {
        return HTTPS_IMAGE . $filename;
    }   
}

the error points to the 3rd line on this code.

Answer 1

You're mixing array and string in a return . Try the following:

• specify an index to $filename (like $filename[0] )

or:

• convert it into a string with for example implode() function (like implode(',', $filename); , which gives you an string with the values of the array $filename , segregated by , ).

Answer 2

You are using a string concatenation operator with something that is not a string. Namely, with an array.

Try this:

function href($filename) {
var_dump($HTTP_IMAGE);
var_dump($filename);
    if (@$_SERVER['HTTPS'] != 'on') {
        return HTTP_IMAGE . $filename;
    } else {
        return HTTPS_IMAGE . $filename;
    }   
}

When you run this code it should display whatever is inside HTTPS_IMAGE and $filename.

As I do not know what they contain, I will explain with the following sample code:

$my_array[0] = 'Hello';
$my_array[1] = 'world';
$my_array[2] = '!';
var_dump( $my_array );

If you execute that code you will obtain the following:

array(3) {
  [0]=>
  string(5) "Hello"
  [1]=>
  string(5) "world"
  [2]=>
  string(1) "!"
}

That is an array. It is a collection of elements, which need to be accessed by index. For instance, to access "world" you need to access it by its index, "1":

echo $my_array[1];

Returning to your example, identify which variable is an array and access it by the appropriate index. You will know which index is by inspecting the result of var_dump().