关于通过shell脚本问题传递参数

Question

Am new to shell script.

my requirement is i have a test.sh shell script file i dont know how to pass args through shell script also.

i my shell script i want o get some of the data via args like

perzonalize browser='FF'

i tried $ test.sh perzonalize browser='FF' and inside script i did

      echo $1 $2 

but it prints like perzonalize browser=FF .i need that quote browser='FF'

How it is possible

Answer 1

Quoting is very critical in shell scripts.

You need to call your script as:

perzonalize "browser='FF'"

And echo 1st argument as:

echo "$1"

which will print string with single quotes:

browser='FF'

Answer 2

echo "$@"

Is probably what you want. It passes each argument along separately. According to the man page: "$@" is equivalent to "$1" "$2" ... *

The important thing is the double quotes. You should almost always expand your shell veriables "$like_this". For some rare cases you want

echo "$*"

This will produce just one string consisting of all your original arguments together, separated by whitespace.