获取范围内所有数字的总和

Question

I have a range from 1 to 5. Each number in that range gets squared.

for x in range(1, 5 + 1):
  x = x ** 2
  print(x)

Doing this, gives me: 1, 4, 9, 16, 25.

That is perfect, but how do I then request the sum of the new numbers in the range so that they equal 55?

Answer 1

Accumulate the sum:

>>> total = 0
>>> for x in range(1, 5+1):
...     total += x ** 2
...
>>> total
55

More preferably, using sum and generator expression :

>>> sum(x**2 for x in range(1, 5+1))
55

Answer 2

alternative square pyramidal number solution (as suggested by M4rtini):

(2*(5**3) + 3*(5**2) + 5)/6

or for general n:

def square_pyramid(x):
    return (2*(x**3) + 3*(x**2) + x)/6

Answer 3

total = 0
for x in range(1, 5 + 1):
    x = x ** 2
    total = total + x
    print(x)
print total

The above should help you out. You want to be storing the sum as you calculate X into another variable. You can then use the sum further along in your program.

Answer 4

一条线：

sum(x**2 for x in xrange(1,6))