如何在.load（）;中包含$（）元素？

Question

I'm trying to print some PHP content inside a simple Javascript call. The first one I got, but I have 2 vars to include, and one of them, must to be inside a .load().

I'll put the code bellow for a better understanding:

<?php

$loadclass = 'filtersin';
$load_address = 'recebimento-filter';
$modal_ID = 'FilterModal';

?>

The JS calling (and what I'm trying to do):

<script>
$(document).ready(function(){
    var loadclass="<?php echo '.', $loadclass; ?>";
    var load_address="<?php echo $load_address, '.php' ?>";
     $(loadclass).load("dialogs/filter_group/",$(load_address) );

});
</script>

Answer 1

Change

 $(loadclass).load("dialogs/filter_group/",$(load_address) );

To

 $('.' + loadclass).load("dialogs/filter_group/" + load_address );

• loadclass is now a class. Notice the .
• Appended load_address properly

Please note.

Description: Load data from the server and place the returned HTML into the matched element.

So, if dialogs/filter_group/recebimento-filter does not return HTML it won't work as expected.

To fix this you can add a rewrite rule to .htaccess

Answer 2

Replace:

var loadclass="<?php echo '.', $loadclass; ?>";
var load_address="<?php echo $load_address, '.php' ?>";
$(loadclass).load("dialogs/filter_group/",$(load_address) );

with

var loadclass="<?php echo '.' . $loadclass"; ?>";
var load_address="<?php echo $load_address . '.php'; ?>";
$(loadclass).load("dialogs/filter_group/" + load_address );

The string concatenatio sign is '.' in php and '+' in javascript, not ','

Simpler:

$("<?='.' . $loadclass ?>").load("dialogs/filter_group/<?= $load_address . '.php' ?>");

In both cases (with your initial values) results in:

$(".filtersin").load("dialogs/filter_group/recebimento-filter.php");