[英]Concisely mapping 2 columns from 2D array to key:value pairs
In this example snippet of code, I selectively convert 2 columns from my 2D array into an object. 在此示例代码段中,我有选择地将2D数组中的2列转换为一个对象。 The 1st column represents the keys, the 2nd represents the values.
第一列代表键,第二列代表值。
I feel like there is a more concise way of codifying this idea without so many lines of code. 我觉得没有这么多代码行,就有一种更简洁的方法来整理这个想法。
var my2dArray = [ ['a',2], ['b',3], ['c',4] ];
var keys = [];
var values = [];
var myObj = {};
for(var row = 1; row < my2dArray.length; row++) {
keys[row] = my2dArray[row][0];
values[row] = my2dArray[row][1];
myObj[keys[row]] = values[row];
}
console.log(prod_compare); // outputs object
In reality, I have a 4 column array. 实际上,我有一个4列数组。 Don't mind the simplicity of
my2dArray
. 不要介意
my2dArray
的简单性。 Is there a way to select these two columns for mapping to an object without having to declare 2 temporary arrays? 有没有一种方法可以选择这两个列以映射到对象,而不必声明2个临时数组?
Your code is fundamentally OK, but it can be more concise without being obfuscated: 您的代码从根本上来说还可以,但是可以更加简洁明了:
var my2dArray = [ ['a',2], ['b',3], ['c',4] ];
var myObj = {};
for (var i=0, iLen=my2dArray.length; i<iLen; i++) {
myObj[my2dArray[i][0]] = my2dArray[i][1];
}
This may convert [['a', 1, 2, 3], ['b', 1, 2, 3]]
to {a: [1, 2, 3], b: [1, 2, 3]}
. 这可以将
[['a', 1, 2, 3], ['b', 1, 2, 3]]
为{a: [1, 2, 3], b: [1, 2, 3]}
。
for(var row = 0; row < my2dArray.length; row++) {
keys[row] = my2dArray[row][0];
values[row] = my2dArray[row].slice(1);
myObj[keys[row]] = values[row];
}
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