request.url Express和Node

Question

Im a newbie on node.js, I just wanted to know how to extract the requested url in this code

app.use(express.static(__dirname+"/public"));

Thank you for your help

Answer 1

As you can see on the static middleware source , a middleware is basic a function that receives the parameters (request, response, next_function) .

So you could create a function that reads the url before it goes to static middleware.

var express = require('express');
var app = express();

var staticfn = express.static(__dirname+'/public');
app.use(function (req,res,next) {
    console.log(req.url);
    var sendStream = staticfn(req,res,next);
    console.log(sendStream.path);
});

app.listen(3000)

As you can see on the send package used by the static middleware, the send function returns a object called SendStream .