将Perl Regex转换为PHP

Question

I have the following Regex in PERL which I need to convert to PHP

if ($referrer_url =~ /\.$domain/) { }

I currently have the following in PHP to match it, but I'm not getting the same results:

if (preg_match("/\.$domain/", $referrer_url)) { }

Can anyone tell me if what I have is the same or if I'm mistaken? Thanks!

Answer 1

我只是猜测您的$ domain可能包含。就像mysite.com，如果是这种情况，则需要在变量上使用preg_quote ：

if (preg_match("/\.".preg_quote($domain, "/")."/", $referrer_url)) { }

Answer 2

If $domain is a regular string you may prefer to use strpos to Find the position of the first occurrence of a substring in a string . This would achieve the same result as using preg_quote with the benefit of being easier to read.

if (strpos($referrer_url, ".$domain") !== false) {
}