[英]What is the Lua equivalent of int(input())?
I'm asking the user for a number using 我要求用户输入一个号码
var = io.read()
and then when I do 然后当我这样做
if var == 1 then
print ("Thing One")
elseif var == 2 then
print ("Thing Two")
else
print ("Thing Three")
This always returns "Thing Three" I am presuming this means I need var to get an integer, like when python uses int(input())
这总是返回“Thing Three”我假设这意味着我需要var来获取一个整数,就像python使用
int(input())
Lua supports an argument to io.read()
call. Lua支持
io.read()
调用的参数。 You can pass *n
or *number
as a string to it so that your input would be a number or nil
. 您可以将
*n
或*number
作为字符串传递给它,以便输入数字或数字nil
。
print "enter a number:"
n = io.read("*number")
if not n then error("invalid input") end
You should also take a light reading of this page of PiL . 您还应该仔细阅读本页的PiL 。
So, your code shall be: 所以,你的代码应该是:
var = io.read( "*n" ) -- or io.read( "*number" )
if var == 1 then
print ("Thing One")
elseif var == 2 then
print ("Thing Two")
else
print ("Thing Three")
end
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