[英]Assembley procedure in pascal code?
I was reading pascal source code when i met this procedure: 遇到此过程时,我正在阅读Pascal源代码:
procedure Copier_Bytewise (const source, target; const Count: word);
(* $ IFDEF VirtualPascal *)
assembler; (* $ Uses ESI, EDI, ECX *) (* $ Frame-*)
asm
mov esi, source
mov edi, target
mov ecx, Count
cld
rep movsb
end;
(* $ ELSE *)
.
(* $ ENDIF *)
This procedure is called wit these arguments : 这些过程称为以下参数:
Copier_Bytewise (Unpacked [WritePosition-Backwards], Unpacked [WritePosition], length);
So, What exactly is being copied?! 那么,到底要复制什么?!
The source address is memory address of: Unpacked [WritePosition-Backwards]
源地址是以下地址的内存地址:未
Unpacked [WritePosition-Backwards]
The destination address is memory address of: Unpacked [WritePosition]
目的地址是以下地址的内存地址:未
Unpacked [WritePosition]
The copied content in bytes is: length
复制的内容(以字节为单位)为:
length
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