[英]How to change a line in a file using SED properly?
I'm trying to use bash's SED command in OS X and failing. 我试图在OS X中使用bash的SED命令,但失败了。
I need to change this line #"phpunit/phpunit:3.7.*",
to the same but without the #
(so like this "phpunit/phpunit:3.7.*",
in my file. 我需要将此行
#"phpunit/phpunit:3.7.*",
更改为同一行,但不包含#
(因此在我的文件"phpunit/phpunit:3.7.*",
。
What is the best way to do that in sed? 在sed中执行此操作的最佳方法是什么?
I tried this: sed -i -e "s/#\\"phpunit/phpunit:3.7.*\\",/\\"phpunit/phpunit:3.7.*\\"," file.txt
我试过了:
sed -i -e "s/#\\"phpunit/phpunit:3.7.*\\",/\\"phpunit/phpunit:3.7.*\\"," file.txt
but that didn't work :( 但这没有用:(
I can see an obvious error, that you use the substitution separator character (the slash) inside the regular expression part. 我可以看到一个明显的错误,即您在正则表达式部分中使用了替换分隔符(斜杠)。 You must escape it, like:
您必须将其转义,例如:
sed -e "s/#\"phpunit\/phpunit:3.7.*\",/\"phpunit\/phpunit:3.7.*\",/" file.txt
An improvement could be to group what you want to keep, like: 可以将您想保留的内容归为一组,例如:
sed -e "s/#\(\"phpunit\/phpunit:3.7.*\",\)/\1/" file.txt
Both solutions yield: 两种解决方案都可以:
"phpunit/phpunit:3.7.*",
I don't use OS X
, so I omitted the -i
switch. 我不使用
OS X
,所以省略了-i
开关。 In linux
is enought -i
with an space following it, but in your system I think you must provide a blank string, like: -i''
but not sure, so test this part. 在
linux
中-i
后面有一个空格是足够的,但是在您的系统中,我认为您必须提供一个空白字符串,例如: -i''
但不确定,因此请测试这一部分。
Why not just use something like 为什么不只使用类似
sed 's/#//' file.txt
And if you need more specificty then 如果您需要更多的特异性,
sed 's/#"php/"php/' file.txt
$ cat input
#"phpunit/phpunit:3.7.*",
Some serious back-slashing later, due to the special characters *
, .
由于特殊字符
*
,,稍后会出现严重的反斜杠.
and /
: 和
/
:
$ sed 's/#"phpunit\/phpunit:3\.7\.\*",/"phpunit\/phpunit:3\.7\.\*",/' input
"phpunit/phpunit:3.7.*",
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