如何检查2行在SQL Server的表中是否具有相同的数据？

Question

I have the following query..now i have to check if the same columns have same data..

Can anyone help me with the query pls

SELECT 
   FirstName, MiddleName, LastName, Company, TaxExempt, 
   AddressTitle, AddressLine1, AddressLine2, City, [State], ZipCode, Country,
   PhoneNumber, EmailID, 
   o.OrderNumber, o.PONumber
FROM 
   CustomerAddresses ca 
    JOIN Orders o 
         ON ca.CustomerID = o.CustomerID
WHERE 
   AddressTitle='Billing'

Answer 1

A common trick is to group by everything and count:

SELECT count(1) as [Count],
   FirstName, MiddleName, LastName, Company, TaxExempt, 
   AddressTitle, AddressLine1, AddressLine2, City, [State], ZipCode, Country,
   PhoneNumber, EmailID, 
   o.OrderNumber, o.PONumber
FROM 
   CustomerAddresses ca 
    JOIN Orders o 
         ON ca.CustomerID = o.CustomerID
WHERE 
   AddressTitle='Billing'
group by 
   FirstName, MiddleName, LastName, Company, TaxExempt, 
   AddressTitle, AddressLine1, AddressLine2, City, [State], ZipCode, Country,
   PhoneNumber, EmailID, 
   o.OrderNumber, o.PONumber

You can add:

having count(1) > 1

at the bottom if you only care about duplicates and don't want to see singles.

Answer 2

Use Common Table Expressions to find all the rows where grouping them produce count larger than one. Then join that result back to the CustomerAddress table to get the ID of each address.

WITH Billing_CTE
  (SELECT FirstName, MiddleName, LastName, Company, TaxExempt, AddressTitle, AddressLine1, AddressLine2, City, [State], ZipCode, Country, PhoneNumber, EmailID, o.OrderNumber, o.PONumber, Count(1) AS [DupCount]
   FROM CustomerAddresses ca
   JOIN Orders o ON ca.CustomerID = o.CustomerID
   WHERE AddressTitle='Billing'
   GROUP BY FirstName, MiddleName, LastName, Company, TaxExempt, AddressTitle, AddressLine1, AddressLine2, City, [State], ZipCode, Country, PhoneNumber, EmailID, o.OrderNumber, o.PONumber HAVING Count(1) > 1)
SELECT ca.CustomerId,
       o.OrderNumber,
       o.PONumber
FROM Billing_CTE b
JOIN Oderers o ON b.OrderNumber = o.OrderNumber
AND b.PONumber = o.PONumber