[英]Split string into an array with regular expression excluding a word
There was a question asked today, that piqued my interest (and subsequently was deleted) where the user wanted to split the following string with a regular expression今天问了一个问题,这引起了我的兴趣(随后被删除),用户想用正则表达式拆分以下字符串
'The 1. cat 2. sat 3. on 4. the 5. mat';
into this array进入这个数组
["cat","sat","on","the","mat"]
there were answers with this expression有这个表达的答案
str.match(/[a-z]+/gi);
which of course returns这当然会返回
["The","cat","sat","on","the","mat"]
The nearest I come come to an answer was with我最接近的答案是
str.match(/[^The][a-z]+/gi);
which returns返回
[" cat"," sat"," on"," the"," mat"]
Of course this can be done, but how?这当然可以做到,但是怎么做呢?
How about怎么样
Javascript Javascript
var str = 'The 1. cat 2. sat 3. on 4. the 5. mat',
arr1 = str.match(/[a-z]+/gi),
arr2 = str.match(/\b[a-z]+/g);
console.log(arr1);
console.log(arr2);
Output输出
["The", "cat", "sat", "on", "the", "mat"]
["cat", "sat", "on", "the", "mat"]
str.match(/\b(?!The\b)[a-z]+\b/gi)
您可以使用此模式:
str.match(/\b[a-z]+\b(?!\s1\.)/gi)
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