如何使用sql查询结果使用date_add

Question

Instead of using(this works):

db_query(UPDATE ost_ticket duedate=DATE_ADD(NOW(), INTERVAL 3 DAY) WHERE ticket_id=10); 

I would like to replace '3' with output from the code below:

$result = mysql_query("SELECT s.grace_period from ost_sla s, ost_ticket t where s.id=t.sla_id and t.ticket_id=10"); 

$row = mysql_fetch_assoc($result);

$ayam = $row["grace_period"];

However when i try this, it doesnt work:

db_query(UPDATE ost_ticket duedate=DATE_ADD(NOW(), INTERVAL '.$ayam.' DAY) WHERE ticket_id=10);

UPDATE: The original code is as below :

db_query('UPDATE '.TICKET_TABLE.' SET isanswered=0, duedate=DATE_ADD(NOW(), INTERVAL 1 DAY), lastmessage=NOW() WHERE ticket_id='.db_input($this->getId())); 

Answer 1

Is db_query a function in your php code? Then it should probably look like this:

db_query('UPDATE ost_ticket duedate=DATE_ADD(NOW(), INTERVAL '.$ayam.' DAY) WHERE ticket_id=10');