带选择框的html表单无法在另一个php页面中获取值

Question

i have a php page called page1.php with this form

<form id="myForm" action="page2.php" method="post">
<label for="name">a label:</label><input type="submit" name="SubmitCar" value="Done" id="fbutton" /> <br />
<br />
<select name="selectCar">
<?php
session_start(); 

$user = "cardatabase";
$password = "";
$host = "";
$database = "my_cardatabase";
$connessione = mysql_connect($host, $user, $password) or die( mysql_error() . " <br/> could not connect to server");
mysql_select_db($database, $connessione) or die( mysql_error() . " <br/> could not connect datbase");

$id = $_SESSION['myid'];

         $query = "select IDCar
                       from Car";

         $result = mysql_query($query, $connessione) or die(mysql_error());
         if( mysql_num_rows($result) > 0 )  {
              $array = array();
              $i = 0;
              while ($row = mysql_fetch_array($result)) {

                $array[$i] = $row['IDCar'];
                ++$i;
                }

              for ($i = 0; $i < count($array); ++$i) {
                    echo "<option value='$array[$i]'>$array[$i]</option>";
                 }
            }
mysql_close();
?>
</select>
</form>

Simply fill the select box from DB. Now here's the problem. When i reach page2.php i need the value of the select box and i tried this

page2.php

<?php
$value = $_POST['selectCar'];
?>

But it's not working, so i tried to use sessions in this way

page1.php

</form>

    <?php
    if(isset($_POST['SubmitCar'])){
    $_SESSION['idAuto'] = $_POST['selectCar'];
    }
    ?>

out of the form, but still not working. What can i do to get this value in page2.php??

Answer 1

Try using this code to build your <option> , and use mysqli when working with the database

 $result = mysqli_query($connessione, $query) or die(mysql_error());
         if( mysqli_num_rows($result) > 0 )  {
             $i=0;
              while ($row = mysqli_fetch_row$result)) {

                    echo "<option value='".$row[$i]."'>".$row[$i]."</option>";
                    $i++;
                 }
            }

Also, it's not indicated to have mysql tables with names in uppercase , or fields with names in uppercase .

Answer 2

Page2.php

You forgot to echo it.

<?php
$value = $_POST['selectCar'];
echo $value;
?>

Answer 3

I found a simple workaround for my problem. It might not be perfect but it works.

1. i deleted the action="page2.php" in the form of page1
2. in page1.php add this code outside the form

This will do the trick

        if(isset($_POST['SubmitCar'])){
        $_SESSION['idCar'] = $_POST['selectCar'];
        header('Location:page2.php');
        }