如何获取单行数据

Question

I have table called RUGS with the data below. How do I write a TSQl query to get the data as shown in Output. I am not familiar with unPIVOT

`cono ARtype days Revenue PPD

140 MCD 5 1000 500

140 MRA 6 2000 600

140 MRA 7 3000 700

141 MCD 1 5000 100

141 MRA 2 6000 200

141 MRA 3 7000 300`

Result

140 MCD 5 1000 500 MRA 6 2000 600 MRA 7 3000 700

141 MCD 1 5000 100 MRA 2 6000 200 MRA 3 7000 300

Answer 1

Given that every cono will have exactly 3 records (as stated in the comments), a cte with row_number can be used with case statements.

If any have less than three records, you will see blanks and zeroes in the results. Any with more than three will not have all records represented.

Here is an example with @RUGS as a table variable:

declare @RUGS table (cono int, ARType char(3), [days] int, Revenue int, PPD int)

insert into @RUGS VALUES
(140,'MCD',5,1000,500)
,(140,'MRA',6,2000,600)
,(140,'MRA',7,3000,700)
,(141,'MCD',1,5000,100)
,(141,'MRA',2,6000,200)
,(141,'MRA',3,7000,300);

with cte as 
(
    select row_number() over(partition by cono order by (select 1)) as rn, * from @RUGS
)

select cono, 
    max(case when rn = 1 then ARType else '' end) as ARType1, 
    max(case when rn = 1 then days else '' end) as days1, 
    max(case when rn = 1 then Revenue else '' end) as Revenue1, 
    max(case when rn = 1 then PPD else '' end) as PPD1,
    max(case when rn = 2 then ARType else '' end) as ARType2, 
    max(case when rn = 2 then days else '' end) as days2, 
    max(case when rn = 2 then Revenue else '' end) as Revenue2, 
    max(case when rn = 2 then PPD else '' end) as PPD2,
    max(case when rn = 3 then ARType else '' end) as ARType3, 
    max(case when rn = 3 then days else '' end) as days3, 
    max(case when rn = 3 then Revenue else '' end) as Revenue3, 
    max(case when rn = 3 then PPD else '' end) as PPD3      
from cte group by cono