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MySQL SELECT语句COUNT错误

[英]MySQL SELECT statement COUNT error

EDIT - Using PHP I made an ODBC connection to a local Access database 编辑 - 使用PHP我与本地Access数据库建立了ODBC连接

I'm getting the following error: 我收到以下错误:

Warning: odbc_exec(): SQL error: [Microsoft][ODBC Microsoft Access Driver]COUNT field incorrect , SQL state 07001 in SQLExecDirect in C:\\xampp\\htdocs\\cpanel\\modelsearch\\test.php on line 37 Error in SQL

I have a feeling some of the syntax is wrong here for an ODBC connection 我有一种感觉,这里的一些语法错误的ODBC连接

$sql="SELECT `ITEM`, `DESCRIPTION`, `CUS_LOC_NAME`, `MECH_REL_BY`, `PM_DESIGN`, `SHIP_ACTUAL`, `HPL`, `WO_LINE`, `SO` FROM `Schedule` WHERE `HPL` <> 'PART' AND (LEFT(`DESCRIPTION`,6)=?) AND (LEFT(`CUS_LOC_NAME`,6)=?)";

This statement works fine in Access, but its not translating to MySQL very well. 这个语句在Access中运行良好,但它不能很好地转换为MySQL。 What syntax am i missing here? 我在这里缺少什么语法?

FULL CODE RECENTLY EDITED TO REMOVE PDO STATEMENT : 最近编辑的完整代码以删除PDO声明

<?php
date_default_timezone_set('America/Chicago');

 $sql="SELECT `ITEM`, `DESCRIPTION`, `CUS_LOC_NAME`, `MECH_REL_BY`, `PM_DESIGN`, `SHIP_ACTUAL`, `HPL`, `WO_LINE`, `SO` FROM `Schedule` WHERE `HPL` <> 'PART' AND (LEFT(`DESCRIPTION`,6)=?) AND (LEFT(`CUS_LOC_NAME`,6)=?)";
 $rs=odbc_exec($conn,$sql);
 if (!$rs) {
   exit("Error in SQL");
 } 

 echo "<table><tr>";
 echo "<th>ITEM</th>";
 echo "<th>DESCRIPTION</th>";
 echo "<th>CUS_LOC_NAME</th>";
 echo "<th>MECH_REL_BY</th>";
 echo "<th>PM_DESIGN</th>";
 echo "<th>SHIP_ACTUAL</th>";
 echo "<th>HPL</th>";
 echo "<th>WO_LINE</th>";
 echo "<th>SO</th></tr>";

 while (odbc_fetch_row($rs)) {
   $item=odbc_result($rs,"ITEM");
   $desc=odbc_result($rs,"DESCRIPTION");
   $cus=odbc_result($rs,"CUS_LOC_NAME");
   $mech=odbc_result($rs,"MECH_REL_BY");
   $pm_design=odbc_result($rs,"PM_DESIGN");
   $ship=odbc_result($rs,"SHIP_ACTUAL");
   $hpl=odbc_result($rs,"HPL");
   $wo=odbc_result($rs,"WO_LINE");
   $so=odbc_result($rs,"SO");

   echo "<tr><td>$item</td>";
   echo "<td>$desc</td>";
   echo "<td>$cus</td>";
   echo "<td>$mech</td>";
   echo "<td>$pm_design</td>";
   echo "<td>$ship</td>";
   echo "<td>$hpl</td>";
   echo "<td>$wo</td>";
   echo "<td>$so</td></tr>";
 }
odbc_close($conn);
echo "</table>";


?>

THE error is at this line: `$rs=odbc_exec($conn,$sql); 错误在这一行:`$ rs = odbc_exec($ conn,$ sql);

This code works just fine when I edit the $sql statement to remove the ands: 当我编辑$ sql语句以删除ands时,此代码工作正常:

$sql="SELECT `ITEM`, `DESCRIPTION`, `CUS_LOC_NAME`, `MECH_REL_BY`, `PM_DESIGN`, `SHIP_ACTUAL`, `HPL`, `WO_LINE`, `SO` FROM `Schedule` WHERE `HPL` <> 'PART'";

So the obvious error is the LEFT() functions. 所以明显的错误是LEFT()函数。 Can someone advise on how to approach this? 有人可以建议如何处理这个问题吗? Also, I'm not sure what the =? 另外,我不确定是什么=? means. 手段。

Your problem was that your query included placeholders ( ? ) for a prepared statement, but you were treating it as a normal query. 您的问题是您的查询包含准备好的语句的占位符( ? ),但您将其视为普通查询。 Prepared statements need to be prepared with odbc_prepare() and then executed with odbc_execute() . 准备好的语句需要用odbc_prepare()编写,然后用odbc_execute()执行。

<?php
date_default_timezone_set("America/Chicago");

$conn = odbc_connect("Prod_Schedule", "", "");
if (!$conn) {
    exit("Connection Failed: $conn");
}

$sql="SELECT `ITEM`, `DESCRIPTION`, `CUS_LOC_NAME`, `MECH_REL_BY`, `PM_DESIGN`, `SHIP_ACTUAL`, `HPL`, `WO_LINE`, `SO` FROM `Schedule` WHERE `HPL` <> 'PART' AND (LEFT(`DESCRIPTION`,6)=?) AND (LEFT(`CUS_LOC_NAME`,6)=?)";

$stmt = odbc_prepare($conn, $sql);
$params = array("value for first ?", "value for second ?");
$result = odbc_execute($stmt, $params);

if ($result) {
    odbc_result_all($stmt);
}
?>

(Who would have guessed there would be a dedicated function for printing a result set as an HTML table!!?) (谁会猜到会有一个专门的函数将结果集打印为HTML表格!!?)

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