[英]call php function in button click
I need to call the PHP function when I click the button in html page. 单击html页面中的按钮时,需要调用PHP函数。
<script>
$(document).ready(function(){
$('#submit').click(function() {
$.ajax({
type: "POST",
url: "hello.php",
}).done(function( ) {
alert( "Data Saved: ");
});
});
});
</script>
<input type="submit" name="submit" id="submit" value="Buy!" />
Hello.php: Hello.php:
<?php
if(isset($_REQUEST['submit']))
{
counterminus();
}
function counterminus()
{
echo "method called";
}
I have tried the above method but its not working properly.I need to print the string in the counterminus() method when i click the button. 我已经尝试了上述方法,但是无法正常工作。当我单击按钮时,需要在counterminus()方法中打印字符串。
<script>
$(document).ready(function(){
$('#submit').click(function() {
var val = $('#submit').val();
$.ajax({
type: "POST",
data:"var="+val,
url: "hello.php",
}).done(function( ) {
alert( "Data Saved: ");
});
}); });
}); });
the above script will POST the variable name var with the value of the submit to hello.php 上面的脚本将POST变量名var与提交到hello.php的值
on hello.php 在hello.php
echo $_POST['var'];
will result in "buy!" 将导致“购买!”
so 所以
if(isset($_POST['var'])){
.....
.....
Everything looks fine to me, except that you do not print the data returned by your AJAX call, which shall be provided as a parameter to your done
callback. 在我看来,一切都很好,但是您不打印AJAX调用返回的数据,该数据应作为已
done
回调的参数提供。
Try this: 尝试这个:
$.ajax({
type: "POST",
url: "hello.php",
}).done(function(data) {
alert( "Data Saved: " + data);
});
if by any case you put the input type="submit" button inside a form tag. 如果您将输入type =“ submit”按钮放置在表单标签中, you should stop the event from executing.. put this at your ajax call.
您应该停止执行事件。将其放在您的ajax调用中。 Because the form will post before the ajax call completes.
因为该表单将在ajax调用完成之前发布。
<script>
$(document).ready(function(){
$('#submit').click(function(e) {
e.preventDefault();
$.ajax({
type: "POST",
url: "hello.php",
}).done(function( ) {
alert( "Data Saved: ");
});
});
});
</script>
pass a variable submit with url 通过url传递变量
try the following code 试试下面的代码
$.ajax({
type: "POST",
url: "1.php?submit=",
}).done(function( data ) {
alert( "Data Saved: "+data);
});
or u can pass values as data 或者你可以将值作为数据传递
$.ajax({
type: "POST",
url: "1.php",
data: {submit:""},
}).done(function( data ) {
alert( "Data Saved: "+data);
});
Use exit in php.
在php中使用exit。 now it returns "method called" string
现在返回“方法调用”字符串
if(isset($_REQUEST['submit']))
{
counterminus();
}
function counterminus()
{
echo "method called";
exit;
}
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.