[英]JSONModel: MKAnnotation & CLLocationCoordinate2D
I am using JSONModel ( https://github.com/icanzilb/JSONModel ) inorder to handle my JSON data. 我正在使用JSONModel( https://github.com/icanzilb/JSONModel )来处理我的JSON数据。 I just have problem related to adding a
CLLocationCoordinate2D
property in my JSONModel
Subclass, in order to respond to the MKAnnotation
protocol. 我只是遇到与在我的
JSONModel
子类中添加CLLocationCoordinate2D
属性相关的问题,以便响应MKAnnotation
协议。 Since the incoming JSON dosen't contain a coordinate field, but seperated fields with Lat & Lon, and since CLLocationCoordinate2D
isn't an object, JSONModel
want let me ignore protocol. 由于传入的JSON不包含坐标字段,而是用Lat&Lon分隔字段,并且由于
CLLocationCoordinate2D
不是对象,因此JSONModel
要让我忽略协议。
This is my code: 这是我的代码:
@protocol Store @end
@interface Store : JSONModel <MKAnnotation>
@property (nonatomic, copy, readonly) NSString *Name;
@property (nonatomic, copy, readonly) NSNumber *Longitude;
@property (nonatomic, copy, readonly) NSNumber *Latitude;
//Can be ignored since it is not an object type.
@property (nonatomic, assign) CLLocationCoordinate2D <Ignore> coordinate;
@end
How can I ignore the coordinate property? 如何忽略坐标属性?
Just check the documentation 只需检查文档
http://cocoadocs.org/docsets/JSONModel/0.11.0/Classes/JSONModel.html#//api/name/propertyIsIgnored: http://cocoadocs.org/docsets/JSONModel/0.11.0/Classes/JSONModel.html#//api/name/propertyIsIgnored:
Here's the code for your model: 这是您的模型的代码:
+ (BOOL)propertyIsIgnored:(NSString *)propertyName
{
if ([propertyName isEqualToString:@"coordinate"]) {
return YES;
}
return NO;
}
Edit: Although what I would do if I were you is to have a custom transformer for the coordinate property that would read the 2 incoming json keys and produce a location struct for you automatically. 编辑:虽然如果我是我将要做的是为座标属性定义一个自定义转换器,它将读取2个传入的json键并自动为您生成一个位置结构。 Just an idea...
只是个主意...
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