使用.bat文件将文件路径复制到txt文件中

Question

How can I use a .bat file to copy only the file paths from a directory?

For example, I have a folder with 1000 files in it. I need a full UNC path for each file put into a text file. This would include the file extension well.

Answer 1

Copy only the file paths:

(for %a in (*.*) do @echo %~DPa) > output.txt

Copy file paths with extensions:

(for %a in (*.*) do @echo %~DPXa) > output.txt

Previous are command-lines; you may include they in a Batch file, if you wish.

Answer 2

It's always surprised me that the DIR command doesn't have an option to display the full path of the files. Anyway, here's a VBScript solution:

With CreateObject("Scripting.FileSystemObject")
    Set Out = .CreateTextFile("c:\text.txt", True)
    For Each File In .GetFolder("c:\some_folder").Files
        Out.WriteLine File.Path
    Next
    Out.Close
End With

Answer 3

Get full paths using the ~f modifier

for /f "delims=" %A in ('dir /a-d/b') do @echo %~fA >> list.txt

Note: Remember to double those percents if using inside a batch file.