查找向量中向量的元素是否存在于另一个向量中

Question

How would I see if the elements in column of vectors or vectors (ruleList) are present in another vector called ntList (not a vector of vectors). I currently have:

for(int j = 0; j < ruleList[0].size(); j++)
{
    for(int i = 0; i < ntList.size(); i++)
    {
        if(std::find(ruleList[0][j].begin(), ruleList[0][j].end(), ntList[i]) != ruleList[0][j].end())
        {   
            ;
        }
        else
        {
            errorList.push_back(ERROR1);
            error = true;
        }
    }
}

I'm getting an error, but I'm not entirely sure why.

error C2678: binary '==' : no operator found which takes a left-hand operand of type 'char' (or there is no acceptable conversion).

Any help would be appreciated. Declarations of vectors:

vector<string> ntList;
vector< vector<string> > ruleList(100, vector<string> (0, "0"));

Answer 1

Depending on what exactly you want to achieve, std::equal or (C++11 only) std::is_permutation may be sufficient. Those algorithms are good enough if you just want to check if the vectors have exactly the same values stored in them and have the same size.

If you want to do more, eg storing the missing values somewhere else, then you may be better off with a hand-written loop. Assuming you are dealing with std::vector in both cases and are not using C++11:

for (std::vector<int>::const_iterator iter_rule_list = ruleList[0].begin(); iter_rule_list != ruleList[0].end(); ++iter_rule_list)
{
    int const value = *iter_rule_list;
    if (std::find(ntList.begin(), ntList.end(), value) == ntList.end())
    {
        // value missing in ntList
    }
}