Bash命令按顺序运行

Question

The problem:

Number of the commands must be executed consequently, written in one-line command:

comamand1; command2; command3;

The very first command is

 sw user_name; 

The problem is that no commands are executed after the sw user_name; one. (the user gets changed though)

Any ideas about how i can execute the string of the commands described above?

PS

bash-3.2$ sw
Sorry, user ehwe is not allowed to execute '/bin/su -' as root on server_name

Guess it explains what the sw is :)

PPS sw stands for /bin/su -

Answer 1

Hoping that you meant "su" and not "sw" . If you wanted to switch as some user and execute set of commands probably you can use -c option. you can try something like this su - chidori -c "date;ls;df"

Answer 2

It sounds to me like sw might be some sort of alias to su . You can check with alias sw . If this is the case, you could probably use chidori's answer, just replace su with sw .

Answer 3

You cannot change the user of a given process; you can only start a new process running as the new user. As such, sw is probably starting a new interactive shell. When that shell exits, the sw command completes, and the next command in your sequence can complete. For example:

$ sw user_name; echo "Second command executes"
$ echo hello
hello
$ exit
Second command executes